Can we find momentum in finite square well potential? If so how can we find it? Does the eigenfunction of momentum operator is same as eigenfunction of Hamiltonian operator?
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Qmechanic
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Possible duplicates: https://physics.stackexchange.com/q/372085/2451 , https://physics.stackexchange.com/q/362305/2451 and links therein. – Qmechanic Aug 12 '23 at 07:39
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I asked about finite well potential – professor T Aug 12 '23 at 07:48
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If the potential well is finite, then the Hilbert space is the same as for the free particle: $L^2(R)$. The momentum operator is the usual one. Its improper eigenvectors are not eigenvectors of the Hamiltonian.

Valter Moretti
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