Equivalency of Atomospheric Pressure on a Surface to Weight Load on Points

Asked Oct 18 '23 at 12:45

Active Oct 19 '23 at 06:04

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I have a flat square of unit area on sea level. I know that the force exerted on it is approximately $ 10^5 N $. How can I equate this to weight loads on its vertices? Is it right to say forces exerted on different locations can be added to give the same amount of force on the entire surface? How will this problem change if the surface is non-planar? The fact that weight loads hanging from a point is different than force exerted on the entire surface confuses me a lot.

Edit: If I can restate my question it would be as : How can I go from distributed force to point force?

edited Oct 19 '23 at 06:04

asked Oct 18 '23 at 12:45

farhad_hep_81

This is unrelated, but it may help - Toppling of a cylinder on a block – mmesser314 Oct 18 '23 at 14:58
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Do you know the difference between a point force and a distributed force? – Chet Miller Oct 18 '23 at 22:01
Thanks for the comment especially because of @ChetMiller I edited my original question. – farhad_hep_81 Oct 19 '23 at 06:07
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Is it a flat surface? Is the force uniformly distributed? Can you provide a schematic for a specific example? (It's hard to visualize exactly what you are asking) – Chet Miller Oct 19 '23 at 11:54

Equivalency of Atomospheric Pressure on a Surface to Weight Load on Points

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