I don't understand why in some texts they put that infinitesimal volume $dV = dx dy dz$. If $ V = V(x,y, z)$ infinitesimal volume should be $$dV = \frac{\partial V}{\partial x} dx +\frac{\partial V}{\partial y} dy + \frac{\partial V}{\partial z} dz$$
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2Would [math.se] be a better home for this question? – Qmechanic Oct 13 '13 at 18:34
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May be, but I posted it here because modern mathematicians almost wiped out the concept of infinitesimal from calculus, although still it is stillwidely used in sciences, like physics. (See http://www.math.oregonstate.edu/bridge/papers/differentials.pdf) So, I thought physicists could better explain me that. – Girolamo Oct 13 '13 at 18:54
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Actually, it's been proved that infinitesimals don't lead to any problems after all. For a discussion at an elementary level, see http://www.math.wisc.edu/~keisler/calc.html . – Oct 13 '13 at 20:17
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2If $V$ is a function, writing $\mathrm dV$ for the volume element is just a bad thing to do. I'd write $\mathrm d^3x$ or $\omega_V$, depending on who's gonna read it. – Nikolaj-K Oct 13 '13 at 22:30
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The volume of a finite box is $\Delta x \Delta y \Delta z$. The infinitesimals are simply thought of as very small deltas -- so small that they're smaller than any real number. (This can be formalized in terms of non-standard analysis.)
What may have misled you was the notation $dV$. This simply means an infinitesimally small volume. It doesn't mean that $V$ is a function being differentiated.
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There are two independent concepts here.
- One is that of an infinitesimal volume, also referred to as a differential volume element. $$dV = dxdydz$$ This represents a small volume that you would use to derive conservation equations for example. See also infinitesimal for a more general definition.
2 .The second is a concept of a differential, $$dV = \frac{\partial V }{\partial x } dx+ \frac{\partial V }{\partial y }dy+ \frac{\partial V }{\partial z }dz$$
This differential represents a change in the linearization of a function.

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