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My question is not about (pseudo) philosophical debate; it concerns mathematical operations and experimental facts.

What is an observer? What are the conditions required to be qualified of observer, both mathematically and experimentally?

Qmechanic
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Isaac
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    I guess we'll have to wait for the next season of Fringe to find out... http://en.wikipedia.org/wiki/List_of_Fringe_characters#September_.28The_Observer.29 – dbrane May 14 '11 at 16:18
  • This is hard to Answer adequately at least because there will be a different Answer for different interpretations of quantum theory. I presume you mean quantum theory? Not that a classical observer is easy to get really straight. My immediate reaction is that you should go to the Stanford Encyclopedia of Philosophy, http://plato.stanford.edu/contents.html, read a few things that come up when you search for "observer quantum", then ask a more specific Question. – Peter Morgan May 14 '11 at 16:26
  • @Peter "no philosophical debate". I know the subject is sensitive. My question accepts the answer "nobody knows". (But I personnally do not guess so; otherwise, how could experiments be done? How could theory be so precise? No matters which interpretation is the correct one, I suppose it can be given at least a few hints.) – Isaac May 14 '11 at 17:11
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    Dear @Isaac, "nobody knows" isn't really an accurate answer. It's more correct to say that we do know that there is no unique answer because the question depends on definition and is associated with no operational way to test it. We talk about observers to express the idea that various properties of physical systems may be "perceived" or measured by some objects, but what is exactly needed for an object to be able to measure "something" with a certain "accuracy" depends on the "something" and the "accuracy", as well as all other details. There is no "universal" answer to all such questions. – Luboš Motl May 14 '11 at 17:20
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    J von Neumann in Mathematical foundations of quantum mechanics (eg Princeton 1955, 1996), Chapter IV.1 explained idea of "observer" and I think it is appropriate introduction (and not only for the history of the problem). For more recent discussion and more references it is possible to see, eg: M. Schlosshauer, Decoherence, the measurement problem, and interpretations of quantum mechanics, Rev. Mod. Phys. (2005), etc, etc. – Alex 'qubeat' May 14 '11 at 23:09
  • Must say, this is an exceptionally important question - one that has very different interpretations amongst top physicists (Neumann, Schrodinger, and others)... I feel that NONE of these answers are satisfactory. – Christopher Bales Apr 11 '19 at 15:58

8 Answers8

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Are we talking quantum mechanics? Then I'd say that a "measurement" is any operation that entangles orthogonal states of the system under consideration with orthogonal states of the environment. "Measurement" is the important thing in most formulations of QM. Colloquially speaking, an observer is something that performs measurements.

The only other place in physics I can think of where "observer" shows up is in the oft-used phrase "This is obvious to the casual observer". This is just shorthand for "I can't be bothered to write out the mathematical proof".

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    I think this pretty much gets it. The main point would be that "observer" is not a precisely defined concept; there isn't any set of mathematical conditions that something has to be considered an observer, for example. – David Z May 14 '11 at 20:55
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    Nice answer. Let me add that a lot of the esoteric fallout from QM is due to people having some wrong ideas about the term "observer", telling you that your consciousness somehow creates the material world. Maybe in more rigorous terms, an observer could be anything that induces decoherence by coupling microscopic quantum states to different states of a macroscopic system. – Lagerbaer May 14 '11 at 21:32
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    A nice secret way to promote the logic of decoherence without using the word, +1. ;-) – Luboš Motl May 15 '11 at 07:48
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    If you define the observer as "something that performs measurements" and measurement as "any operation that entangles states of the system under consideration with states of the enviroment" you could realize that you need an observer of the observer to say that measurement was really done, this is in the Schrödinger's Cat paradox, it's not enough the operation itself, you need an observer of both things to define an observer, Schrödinger could perfectly realize that a cat is enough for wave colapse(old ugly word) or decoherence, but he put an observer outside the box of his thought experiment. – HDE May 17 '11 at 18:12
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    What is an example of an orthogonal system performing the "measurement" operation? I know that a person is such an entity, but an electron is not, because if it was, it would collapse the wavefunction of its atom, which is not what we observe. – sqykly Mar 10 '17 at 21:04
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    In addition, this definition is not helpful if both the system and environment are wavefunctions. In order to perform a measurement, a classical (non-entangled) instrument is required. In a universe completely described by QM, where does the classical instrument come from? – sqykly Mar 10 '17 at 21:12
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    This seems to suggest that any interaction is a measurement and shifts the question to "is anything ever not being measured"? – Praxeolitic Jun 12 '18 at 00:53
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Either the observer is classical or the observer is quantum. If the observer is classical, we are back to the Heisenberg cut of the world into a quantum part and a classical part, and the explanatory gap needs to be bridged in this manifestly dualistic interpretation. If the observer is quantum, then another observer needs to observe the first quantum observer by the tenets of quantum mechanics. Down the road of infinite regress we go.

As long as the concept of an observer can't be made mathematically precise and unambiguous, the measurement problem will never be solved.

Phil
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  • This is a fine answer unless we observe classical systems that corroborate about quantum systems. Humans are one example of classical systems that force a quantum system to converge on one state, and all humans then agree on the outcome. Please provide another example of a system, classical or quantum, that will produce converging measurements of a quantum system. Keep in mind that individual classical particles like free electrons or photons are integrated into quantum systems without classicalizing them. – sqykly Mar 10 '17 at 21:41
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I prefer a variant of Anonymous Coward's answer given above, by leaving out the environment. I would say that an observer is a system that interacts with the systems it observes by entangling orthogonal states of the systems under consideration with orthogonal states of itself and possibly other systems.

So, I don't bring in the baggage of an environment here, but the possibility of that is included by mentioning "other systems". The fundamental point is that an observer is capable of extracting information from a system. A simple example is the CNOT gate which in the |0>,|1> basis acts on two qubits by applying the NOT operation on the second qubit if the first qubit is |1> and acts as the identity otherwise. This means that when the second qubit in initialized in the |0> state, it can "measure" the first qubit. The observer is thus the CNOT gate, the second qubit is its record of the observation it has made.

Count Iblis
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    Can the CNOT gate be entangled with some other system, or is the record it has extracted fully classical with no possibility of diverging into a superposition-like, incoherent state? Also can you provide a reference demonstrating the implementation of a working CNOT gate? – sqykly Mar 10 '17 at 21:54
  • A CNOT gate is a unitary transformation acting on 2 qubits; it is not (pun not intended) a measurement in the usual quantum mechanical sense of an operation that results in a real value and "collapses" the state of the system. One simplest example of a measurement device is the Stern-Gerlach apparatus. – hft Oct 12 '23 at 16:43
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I'd say, "observer" is an arbitrary entity which converts quantum information into classical. Classical information is, roughly, anything that can be duplicated without distortion and transmitted. The need for classicality is anthropic: we are conditioned by evolution to share information for survival and to value "rational thought" whose main defining characteristic is that it can be repeated.

mho
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    Quantum information is not turned into classical information. When an observation happens the observer and the observee become entangled so the quantum information of the observee is replaced with a correlation between the two subsystems. Each different state of he observer correlated with different states of the observee now only has access to that state, this reduced information can be copied because while you can't copy an unknown state you can copy a known state. – Timaeus Aug 11 '15 at 17:30
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There are Copenhagen idealists out there who insist the wavefunction or density state lies entirely in the subjective mind of the observer. There is no objective reality out there except in the mind of the observer.

Let me tell them whatever the contents of the conscious mind, the contents are classical information about an alleged world out there. At best, the contents of consciousness can only pick out POVM elements from some predetermined POVM. Where in Nature is the information contained in the wavefunction or density state or path integral or some other beable stored? Certainly not in the contents of consciousness themselves. If such information are stored nowhere, how does Nature manage to keep track of what it is supposed to do and get the sampling probabilities for the POVM right? But if such information are stored elsewhere, then there is an element of reality outside the conscious mind of the observer.

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While my previous answer is entirely valid, the same can be explained using more traditional terminology.

To be simple, observer is a physical system that is capable of triggering collapse of the wave function once it comes into a contact with a quantum system.

Which system can trigger wave function collapse is only determined experimentally. But what is known for sure is that any system that is in thermodynamic contact with the observer (or is not thoroughly isolated from it) also can trigger the wave function collapse.

It is experimentally determined that the Earth's environment and atmosphere are capable of triggering the wave function collapse, which means that they are also in thermodynamic contact with the observer.

On the other hand in well isolated and cooled interior of D-Wave Systems' Orion quantum computer the collapse of wave function does not happen unless a contact with the exterior is made intentionally which allows to perform quantum computations which could not be made otherwise.

This hints that there is no observer inside this well-isolated box. By gradually expanding such box and putting more and more matter inside it it is possible in principle to find the actual point that acts as an observer and triggers the collapse.

This is not practically possible unfortunately, because any living organism cannot exist at such low temperatures which are needed for through isolation and its high level of entropy will make any action on it virtually irreversible thus not allowing to test whether the collapse actually happened.

Anixx
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    Why bother with the qualification of the "live" observer? If you are correct that the exchange of information reaches a critical point at which it will fail to compute, would it not suffice to hook up an array of N D-Waves with IO to each other, and then error check it at the end with a traditional CPU? Is there any non-proprietary counterpart to the D-Wave whose details I can examine? – sqykly Mar 10 '17 at 22:27
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    I actually liked this answer. It might not be a very standard explanation, but it contains some interesting points. – samvv Jul 23 '19 at 17:20
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In contrast to the association of an observer with a living being that makes an observation in classical mechanics, in quantum mechanics (qm), an observer is not associated with a conscious being. In qm an observer is a physical process that interacts with a normalized superposition of $N$ different quantum states after which the superposition collapses into a normalized superposition consisting of $n<N$ different quantum states (unless infinity is involved like in the first example I give), $n$ depending on the physical process used. For example, if the physical process of a traveling normalized photon wavefunction, which is a superposition of infinite photons with different energies (a wavepacket), and this physical process) overlaps with the position wave function of an elementary particle, consisting of an infinite number of position eigenstates (Dirac distributions), the position wavefunction will collapse (if it has a broader spatial extension than the spatial extension of the photon wavepacket) into a new normalized wavefunction, but with less spatial extension. In this case, both $N$ and $n$ are infinite, both the photon wavepacket nevertheless "took infinite position eigenfunctions of the position wavefunction away" by letting it collapse to a smaller size.
Now consider a normalized superposition of two electron spins (say $\sqrt{\frac{1}{2}}|s_{up}\rangle+\sqrt{\frac{1}{2}}|s_{down}\rangle$. When a uniform magnetic field (the physical process) is imposed on this wavefunction, the magnetic field lets the superposition collapse in one of the two new normalized states (with equal probability) $|s_{up}\rangle$ or $|s_{down}\rangle$.
So in the case of qm an observer in the form of a conscience being ain't necessary. Of course, a macroscopic conscience being is necessary to observe the results of the collapsed wavefunctions, but they are not necessary to make normalized wavefunctions collapse.
There is a widespread interpretation that says that the collapse only takes place after a conscient observer (like us human beings) has observed the superposition,i.e. after, for example, the collapse of the superposition of the two spins of the electrons doesn't take place direct after the interaction with the magnetic field but only when we observe the process. In fact, when we adopt this interpretation conscient observers couldn't have evolved in the course of history. When no conscient observers were present no collapses of wavefunctions could appear. Only superpositions of wavefunctions would be present and the superpositions would only increase in time. That being the case no macroscopic conscient observers could have developed at all.

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Observer is a special person (or a system that contains such person) which does not obey the usual laws of quantum mechanics. While it is much easier to define observer from a philosophical point of view, the mathematical answer is that the observer is a system which manifests subjective decoherence when observed. For the definition of subjective decoherence and precise mathematical formulations, refer to this work.

Anixx
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    Sorry, all systems obey the laws of quantum mechanics, whether they're observers or not. – Luboš Motl Jan 03 '13 at 12:00
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    @Luboš Motl It has been shown that universally-valid theories are not possible. A theory can be only universally-valid in a relative sense, that is valid for any system, not including observer. See here: https://homepages.fhv.at/tb/cms/?download=tbDISS.pdf – Anixx Jan 03 '13 at 15:42
  • Isn't subjective decoherence the same as quantum entanglement? An electron's up-spin state observes its entangled electron in its down-spin state and vice versa. If an electron could think, if you'd talk to it, it would tell you the other electron always has been in a down-spin state. – John Dvorak Dec 20 '14 at 11:13
  • Updated link: https://homepages.fhv.at/tb/tb/cms/index.html%3Fdownload=tbDISS.pdf – Anixx Oct 28 '23 at 14:09