Questions tagged [kinematics]

The description of the movement of bodies by their position, velocity, acceleration (and possibly higher time derivatives, such as, jerk) without concern for the underlying dynamics/forces/causes.

When to Use this Tag

Use to discuss the movement of a body in terms of position, velocity, acceleration (or, in principle, higher derivatives thereof, such as, jerk) without concern for the forces/dynamics causing this movement.

Introduction

The classical description of the movement of a (point-like) body consists of three vector quantities, defined in a suitable background coordinate system (usually $\mathbb{R}^n$ for n-dimensional problems).

  • The position of the body, usually denoted by either $\vec x(t)$ or $\vec q(t)$ as a function of the time $t$.
  • The first total time derivative of the position of the body, defined to be the velocity $v(t) \equiv \frac{\mathrm{d}\vec x(t)}{\mathrm{d}t} $.
  • The second total time derivative of the position of the body, defined to be the acceleration $a(t) \equiv \frac{\mathrm{d}\vec v(t)}{\mathrm{d}t} = \frac{\mathrm{d}^2\vec x(t)}{\mathrm{d}t^2} $.

Special Cases

Constant Velocity

Problems in which some body travels with a constant velocity are common introductory exercises and can be solved with the difference version of the definition of velocity:

$$ \vec v = \frac{\Delta \vec x}{\Delta t} = \frac{\vec x - \vec x_0}{t - 0}\quad,$$

where we take the body to be at position $x_0$ at time $t = 0$.

Constant acceleration

In some problems, the acceleration of the body is a constant $\vec a_0$, for example $\vec g$ during a free fall close to the surface of Earth. In this case, it is easy to integrate twice to calculate the position $\vec x$. With initial conditions $\vec x(0) = \vec x_0$ and $\vec v(0) = \vec v_0$, we have:

\begin{eqnarray} \vec a(t) & = & \vec a_0 \\ \vec v(t) & = & \vec a_0 t + \vec v_0 \\ \vec x(t) & = & \frac{1}{2} \vec a_0 t^2 + \vec v_0 t + \vec x_0 \end{eqnarray}

Constant Jolt

, or is the rate of change of acceleration with respect to time; i.e. $\vec j=\frac{\mbox{d}\vec a}{\mbox{d}t}$. In the case of a constant jolt, one may trivially apply the Taylor expansion (or through algebraic means) to find that:

\begin{eqnarray} \vec j(t) & = & \vec j_0 \\ \vec a(t) & = & \vec j_0 t + \vec a_0 \\ \vec v(t) & = & \frac{1}{2} \vec j_0 t^2 + \vec a_0 t + \vec v_0 \\ \vec x(t) & = & \frac{1}{6} \vec j_0 t^3 + \frac{1}{2} \vec a_0 t^2 + \vec v_0 t + \vec x_0 \end{eqnarray}

4278 questions
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Should you run when under rain?

When it's raining, would you get less wet if you run or more wet? I think you will get less wet, because rain is coming down in a constant volume and if you run you will have a shorter amount of time you will get less volume I'm not too sure though,…
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What's my weight when jumping on a bicycle from a higher to a lower ground?

Before I start defining the situation and asking a question, I'd like to make a few things clear: this is not a homework, merely a matter of personal interest and enthusiasm I am neither a physicist, nor a native English speaker, therefore I…
Frantisek
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View from a helicopter rotor: why is the horizon distorted?

This video ("rotor panorama") was captured by a camera attached to the rotor head of a radio-controlled helicopter, with the frame rate set to the rotor's frequency. During a long segment of the video, the horizon looks distorted: What causes this…
Nutel
  • 161
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What does the derivative of velocity with respect to position mean?

According to a Physics book, for a particle undergoing motion in one dimension (like a ball in free fall) it follows that $$\frac{dv}{ds} = \frac{dv}{dt} \frac{dt}{ds} = \frac{a}{v},$$ where $v$ is the velocity and $s$ is the position of the…
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Can an object reverse its direction of acceleration even though it continues to move in the same direction?

Can anyone please explain me on this matter along with day to day examples?
Flare'D
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Cue Ball Moving on a Train Problem

Imagine a pool table on a train, and ball on the pool table. The train's forward direction is to the left. Imagine a completely horizontal force applied on the cue ball to the right. The path of the cue ball however, is as shown by the orange line…
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Is it possible to rotate an angle on perfectly smooth ice?

You must start and end with the same pose. Prove it if you think you can't.
xzhu
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when to consider linear kinetic energy and when to use angular kinetic energy?

I saw a problem about a pivoting rod online (http://dev.physicslab.org/Document.aspx?doctype=3&filename=RotaryMotion_RotationalDynamicsPivotingRods.xml), I am thinking the problem if we initially hold the rod horizontally with one end hinged on the…
user1285419
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Expressing a specific motion from the point of view of a different rotating coordinate system

Simplified problem presentation I am trying to describe a specific motion from a point of view of a moving coordinate system. To make easier the comprehension I created this childish animation, where Mickey Mouse's face (expressed in the local…
Richard
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Is velocity the derivative of position, distance, or displacement?

All over the internet, I am seeing different people defining velocity as the derivative of either position, distance, or displacement and it is really confusing me. I can understand how the derivative of position is velocity because the very…
user225790
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How do I find minimum constant deceleration so that object does not pass distance d in time t?

I'm working on a problem for an online judge site. I've boiled down the problem to this calculation: given a vehicle with an initial velocity $v$, how can one calculate the minimum constant deceleration $a$ required to make sure the vehicle does…
Bogatyr
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Transformations and kinetic energy

From the equation $E_k=\frac12mv^2$ you can determine more energy is necessary to accelerate a mass the higher your initial velocity is. For example, three times more energy is necessary to accelerate a mass from 1 m/s to 2 m/s than from 0 m/s to 1…
J Physics FM
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Writing the fourth kinematic formula ($v^2 = v_0^2 + 2a \Delta x$) in a different form

I have noticed that if we play with the formula a bit, we get \begin{align} v^2 &= v_0^2 + 2a \Delta x \\ \frac{(v+v_0)}{2} \cdot (v-v_0) &= a \Delta x \\ \overline{v} \cdot \Delta v &= a \Delta x \end{align} Meaning the average velocity…
Ak2399
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Confusion about the value of normal force on a wedge

I was solving a banking problem when I had the following doubt. We have a mass m on a wedge having an angle A. We have to find the normal force acting on the block of mass m. I tried to decompose the force mg acting in downward direction into two…
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Why do the following two constant acceleration equations produce contradicting outputs?

Let acceleration = -a. I'm was originally trying to find the stopping distance in terms of $v_0$ and $a$ Two relevant equations of linear motion with constant acceleration then become $x = \frac12(-a)t^2 + v_0t$ $0 = v_0 - at$ Now if i substitute…
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