Let's assume two waves with same phases and same wave speed $c$ in the same plane overlap, thus creating a constructive interference.
The elongation and speed of both waves is added to create the new interference wave:
$$s_{1} + s_{2} = s_{3}$$ and $$v_{1} + v_{2} = v_{3}$$
Due to energy conservation, the sum of kinetic energies and potential energies of waves 1 and 2 should be equal to the kinetic and potential energy of wave 3. Simplifying and using the same mass each time:
$$\frac{mv_{1}^{2}}{2} + mgh_{1} + \frac{mv_{2}^{2}}{2} + mgh_{2} = \frac{m(v_{1}+v_{2})^2}{2} + mg(h_{1} + h_{2})$$ $$\frac{mv_{1}^{2}}{2} + \frac{mv_{2}^{2}}{2} = \frac{m(v_{1}^2+v_{2}^2 + 2v_{1}v_{2})}{2}$$ $$0 = mv_{1}v_{2}$$ Obviously I'm forgetting something here, but what?