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From the link Is non-mainstream physics appropriate for this site?

"a question that proposes a new concept or paradigm, but asks for evaluation of that concept within the framework of current (mainstream) physics is OK."

Here is a concept, evaluation within the framework of current (mainstream) physics would be welcome.

Is it possible that an expansion of all length scales can be happening, as in the cartoon below?

enter image description here

It shows all lengths increasing, the size of atoms, people, stars and the distances between all objects. Each physical quantity and constant varies depending on the number of length dimensions in it. For example since Planck's constant has a length dimension of 2, so it's change with time is

$h=h_0e^{2Ht}$

where $H$ is an expansion constant and $t$ is time.

\begin{array}{c|c|c} {quantity} & {length-dimension} & {change}\\ \hline length & 1 & e^{Ht}\\ mass & 0 & constant\\ time & 0 & constant\\ h & 2 & e^{2Ht}\\ c & 1 & e^{Ht}\\ G & 3 & e^{3Ht}\\ Area & 2 & e^{2Ht}\\ \end{array}

etc...

Can this type of expansion be ruled out A) locally or B) by distant measurements e.g. of distant stars or galaxies, from within mainstream physics?

The expansion referred to occurs for the whole universe. It's proposed as there could be another reason for the redshift of light from distant stars. If the energy of a photon is conserved during flight, but was emitted when Planck's constant was lower, then from $E=hf$, the frequency of the received photon would be lower and the light from a distant star would be redshifted.

A bounty has now been added. A convincing reason why the above type of expansion cannot be occurring would be welcome.

Here is the work done so far.

It is to determine the apparent matter density that would be concluded in a flat universe, with a matter density of $1.0$ and the type of expansion above.

It leads to the conclusion that the matter density would be measured to be $0.25$ or $0.33$ from galaxy clusters and supernovae data respectively. A Diagram of supernovae data is below and then more details of the calculations.

enter image description here and enter image description here

The diagrams show the distance modulus predicited by the type of expansion in the question, top curve. Concordance cosmology with a matter density of 0.3 and 1.0 are the middle and bottom curve respectively. The second diagram is an enlargement of the first.

Matter density from Galaxy Clusters etc...

Traditionally the scale factor of the universe at redshift $z$ is

$a=\frac{1}{1+z}\tag{1}$

If the energy of the photon is conserved during flight, from $E=hf$ and $h=h_0e^{2Ht}$

For an emitted wavelength of $\lambda_1$

$z=\frac{\lambda_1e^{2Ht}-\lambda_1}{\lambda_1}$

$1+z = e^{2Ht}=a^{-2}$ ,

($a$ decreases with increasing $z$ in an expanding universe) so

$a=\frac{1}{\sqrt{1+z}}\tag{2}$

For small distance $d$

$\frac{v}{c} =z= e^{2H\frac{d}{c}}-1=\frac{2Hd}{c}$

$v=2Hd\tag{3}$

i.e. Hubble’s law is still valid but we identify the expansion parameter $H$ with half of Hubble’s constant $H_0$

this leads to the conclusion that the matter density will be measured to be $\frac{1}{4}$ of the true value, as follows.

$\Omega_m = \frac{\rho}{\rho_{crit}}\tag{4}$

$\rho_{crit}=\frac{3H(z)^2}{8\pi G}\tag{5}$

If the value for $ H(z)$ used in $\rho_{crit}$ is twice the true value, then the apparent matter density would be measured as $0.25$ instead of $1$.

Matter Density from Supernovae Data.

In LCDM the Hubble parameter is

$H(z)=H_0\sqrt{\Omega_m {(1+z)}^3+\Omega_k{(1+z)}^2+\Omega_\Lambda}$

The comoving distance is obtained from

$D_M=\int_0^z \frac{c}{H(z)} dz$

Using a flat universe approximation, omitting $\frac{c}{H_0}$ and using $m$ for $\Omega_m$ ,the comoving distance, for small $z$ is

$\int_0^z(m(1+3z+3z^2+\dots )+1-m)^{-\frac{1}{2}}dz$

$=\int_0^z(1+3mz+3mz^2)^{-\frac{1}{2}}dz =\int_0^z(1-\frac{3}{2}mz+\dots)dz$

$=z-\frac{3mz^2}{4}\tag{6}$

For the type of expansion that we hope to rule out,

The co-moving distance is

$D_M=\int_t^0 \frac{c}{a(t)} dt$

$a=\frac{1}{\sqrt{1+z}}$

$\frac{da}{dt}=\frac{da}{dz} \times \frac{dz}{dt} ={-\frac{1}{2}(1+z)^{-\frac{3}{2}}}\times\frac{dz}{dt}$

$H(z)=H=\frac{\dot{a}}{a}=\frac{-1}{2(1+z)}\times\frac{dz}{dt}$

$dt=\frac{-1}{2H(1+z)}dz$

$D_M=\int_0^z \frac{c}{2H}{(1+z)}^{-\frac{1}{2}} dz$

$D_M=\frac{2c}{H_0}(\sqrt{1+z}-1)\tag{7}$

again omitting $\frac{c}{H_0}$ and for small $z$, $(7)$ becomes

$2(1+\frac{1}{2}z-\frac{1}{8}z^2-1)$

$=z-\frac{z^2}{4}\tag{8}$

there is a match between $(6)$ and $(8)$ if $m=\frac{1}{3}$

So we conclude from Galaxy and supernovae data, or combinations of data sets, that the matter density would be measured, with the type of expansion in the question, at between $0.25$ and $0.33$. As it is measured at this value, it's concluded that the expansion cannot be ruled out this way. A diagram with supernovae data is above.

Is there a convincing reason why the expansion described should be ruled out?

John Hunter
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    The gauge principle originally came from Weyl postulating such a scale invariance inspired from the principle of relativity. Weyl showed his work to Einstein who said it was more mathematics than physics. It took another fifty years before it found its correct formulation ... – Mozibur Ullah Mar 13 '21 at 10:46
  • That's interesting, Einstein's comment that it was mathematical sounds as though he thought it had no meaning physically, it can easily be assumed that such an expansion is meaningless as no change can ever be measurable. But can a physical meaning be found if we compare length scales here to those far away, i.e. in a totally static universe they would be the same, but in such an expanding one, they are larger now than they were before and larger than they were when light left a distant star. Have any cosmological models been developed incorporating the type of expansion described? – John Hunter Mar 13 '21 at 10:54
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    Related, and links therein. – rob Mar 13 '21 at 11:13
  • There have been articles wondering something similar, if we also identify the expansion constant with the Hubble parameter, then since the redshift depends on $2H$ then the true 'expansion parameter' is half of the Hubble parameter. It has the advantage that when we work out the matter density from $\frac{\rho}{\rho_{crit}}$ since the denominator depends on $H^2$ it works out as 0.25 and may account for the apparent dark energy phenomenon – John Hunter Mar 13 '21 at 11:20
  • @John Hunter: Thats roughly right. Weyl was looking for a local invariance of scale. Gauge, in one sense of the word means scale. So your non-mainstream example is very mainstream, it just happens to be carefully hidden away under many layers of technical jargon! – Mozibur Ullah Mar 13 '21 at 11:33
  • How does this differ from changing your system of units? There is no way to meaningfully say whether physical constants with dimensions are changing with time, only dimensionless ratios like the fine structure constant. – ProfRob Mar 17 '21 at 16:00
  • There seem to be a few comments saying it's the same as a change of units. Imagine a country with high inflation. On Monday a loaf of bread costs 2 units and a person earns 50 per day. On Tuesday it's 20 for bread and the person earns 500. The change of units doesn't seem to matter, you can still buy 25 loaves per week. But if someone owes you for a loaf of bread, they post 2 units on Monday which arrives on Tuesday. The 2 units is not enough for you to buy a loaf. That's the difference between a change of units and a continually expanding universe of the type described. – John Hunter Mar 17 '21 at 22:53
  • Any other answers would be welcome. Perhaps there are some cosmologist out there, who can explain what measurements have been made to convincingly rule out the type of expansion described... – John Hunter Mar 21 '21 at 23:05
  • @ProfRob I think the OP is suggesting there would be a meaningful way to determine whether physical constants were changing and that would be light would stay constant showing shift – Bill Alsept Apr 13 '21 at 02:10
  • https://physics.stackexchange.com/questions/78684/is-it-possible-to-speak-about-changes-in-a-physical-constant-which-is-not-dimens @BillAlsept – ProfRob Apr 13 '21 at 06:37

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Mainstream physics/cosmology says that local systems that are held together e.g. by gravity or electromagnetic forces do not take part in the global expansion. Our solar system had the same size billions of years ago (there is certainly no evidence to the contrary) and atoms in galaxies billions of light years (in space and time) away have the same size as those locally (as one can conclude from the spectra of distant objects).

See also this reference https://arxiv.org/abs/gr-qc/0508052

Anyway, if your ruler expands as well (like you have drawn above) there would not be an expansion of the universe in the first place, as you would always measure the same distance to a galaxy.

Urb
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Thomas
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  • but when we look at the spectra of distant objects, they are redshifted and the photons have a reduced energy. This would be what we would see if the atoms in the distant object were smaller than the same type of atom today. – John Hunter Mar 13 '21 at 17:06
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    @JohnHunter Smaller atoms would have a higher (negative) energy (electrons are closer to the nucleus) so they would emit a blue-shifted spectrum. But if you subtract the redshift, the frequencies are not blue-shifted. See also this reference https://arxiv.org/pdf/gr-qc/0508052.pdf – Thomas Mar 13 '21 at 17:21
  • we have to include everything i.e. there are formulae for energy levels e.g. $E=\frac{-Zk}{r}$ but when we look at the units of $k$, related to the Coulomb constant, it has units of $[L^3]$, the overall effect is that the energy of an emitted photon is proportional to $L^2$, which it has to be, as it's an energy. The emitted photons from the smaller atom would have less energy and be redshifted – John Hunter Mar 13 '21 at 17:47
  • @JohnHunter The Coulomb constant is just that, a constant. It does not depend on the distance of the charges (by the way, you forgot the charges in your equation for the energy). The gravitational constant is not changed either by the expansion of the universe (there have been some (non-mainstream) theories that propose a variable G but there is no observational evidence for this) – Thomas Mar 13 '21 at 18:14
  • The gravitational constant is also not changed by the expansion in the question, not in a measurable way anyway, so is not ruled out by Lunar Laser Ranging for example. You're point that mainstream physics says that local systems are held together by gravity and do not take part in the expansion is true (i.e. it does say that). – John Hunter Mar 17 '21 at 15:28
  • @JohnHunter Why wouldn't the radiation wavelength expand as well? – user253751 Jul 29 '21 at 10:23
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the frequency of the received photon would be lower

Why would it ? Since $c=\lambda f$ and $c$ and $\lambda$ change in the same proportion then $f$ is constant. All you are doing is changing the units in which length is measured. You get exactly the same effect if you measure the wavelength in furlongs instead of metres, and denominate the speed of light in furlongs per second - frequency remains unchanged.

gandalf61
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  • It's different to a change of units. The energy of the emitted photon was $E=hf$ at a time when both the energy of the photon and Planck's constant were lower. Then when the photon arrives here Planck's constant has increased. If the energy of the photon is conserved during it's journey, then the measured frequency would be reduced. – John Hunter Mar 13 '21 at 16:28
  • @JohnHunter But if the length scale changes then units of energy also change since dimensions of energy are $ML^2T^{-2}$. So the value of $E$ changes numerically in the same proportion as $h$. Once again, $f$ is unaffected. If you insist on some new principle that means that $E$ does not change numerically if the length scale changes then you have moved away from mainstream physics. – gandalf61 Mar 13 '21 at 16:37
  • The energy of the photon is conserved as no time passes for it. The $t$ in the equation is the time that is observed to pass for the object. Can you think of a way either locally or with measurements at a distance to rule out such an 'expansion'? – John Hunter Mar 13 '21 at 16:42
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    @JohnHunter If you change the length scale uniformly for everything then the laws of physics are unchanged, so no measurement would detect this change. But this is trivial - it is just the same as if I use metres as my unit of length today and furlongs tomorrow. You seem to be trying to make a change of units sound profound. I am done here. – gandalf61 Mar 13 '21 at 17:29
  • The change of units is like this: Imagine you had a friend in another town who agreed to send you a 1 metre shoelace because you have one but need another and he/she has lots. It takes a day to arrive in the post. You are then using furlongs. You measure it and call it 1 furlong in length, but it still fits your shoe. The changing of length scales is like this: Your friend sends you a 1m shoelace, but when it arrives your shoes have grown, your other shoelace has a length of 1 furlong and the one that was sent doesn't match it or fit your shoe. – John Hunter Mar 13 '21 at 23:52
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    @JohnHunter: but according to your assumptions, the shoelace should have grown as well (in the change of length scale case), so you would not notice the change in length scale. However, if your friend has performed quality control by measuring the lowest resonant frequency of light being reflected back and forth between the ends of the shoelace, and he tells you the number, you will notice that the frequency was higher in the past (because the shoelace was smaller then) than what you measure for the showlace after it has arrived. – oliver Mar 17 '21 at 11:17
  • The shoelace represented a photon of light, and it's length represented energy, as no time passes for it, the energy of the photon was conserved - in the same way the shoelace length was the same when it was in the post. The shoelace example was a way to indicate that there is a difference between a change of units and the expansion described. – John Hunter Mar 17 '21 at 22:38
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I ll just simply write couple of reasons why its not possible.

  1. If you are talking about everything getting bigger in size then the measurement devices (such as rulers, etc) will also get bigger at the same amount. So even that is the point theres no real way of measuring it. So its not reasonable to talk about it. I can also argue that everything is getting smaller ? Can you argue that as well ?

  2. The force between the two electrons is about $10^{40}$ times larger than the gravitational force. If the expansion of the universe does not have any effect in our solar system (which is governed by gravitational force), then clearly (and logically) the expansion of the universe cannot have any effect on the atomic-scales.

  3. From a simplest point of view, if just my size increases but my mass stays the same my density must get lower and lower which is not the case for me or for any other object that is around you.

  4. Occam's razor - Why everything should be expanded at the same amount in the first place ? Whats the point ?

seVenVo1d
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  • Observational evidence (assuming the type of expansion in the question) is that H is positive. 2. The type of expansion in the question does affect the size of the solar system. 3. How would you measure density?, if you did it by seeing if an object floats or sinks in a liquid, the density of the liquid would have changed too. If it's from $D=M/V$, the lengths to measure $V$ would seem unchanged as your ruler has changed too. 4. Occam's razor, yes, it's simplest that everything expands equally, why should the distance between galaxies expand but other objects not!
  • – John Hunter Mar 17 '21 at 12:15
  • @JohnHunter@I am saying that if everything expands at the same amount you cannot detect the expansion. That's actually the proof that why we can measure that the universe is expanding. Everything is expanding at the same rate (for instance $H$) we would not be able to observe that. 2) No. It does not effect. 3) I am not talking about the measurements but the "physical effects" of being less dense. 4) Okay I am claiming that everything is getting smaller by the same amount argue that please – seVenVo1d Mar 17 '21 at 12:29
  • It's a good point that everything could be getting smaller. then $H$ would be negative, to regain symmetry we could say that it happens in an antimatter universe in which time is negative too, then $-H\times-t$ becomes positive. This could be the reason why we seem to live in a matter universe, i.e. if time was reversed matter would be antimatter, but still perceived as matter, $H$ and $t$ would become negative but still perceived as positive. – John Hunter Mar 17 '21 at 15:01