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This question might have been asked so many times, but here we go again. I'm wondering what homogeneity of space means. All the descriptions say:

  • there's no special point in space, every point looks the same. or

  • laws of physics are the same.

Can we explain more what "laws of physics are the same" mean? I'm first wondering what this means for free particle and then, particle moving when force acts on it. Maybe good examples would enlighten the situation for me in both cases(free and non-free particle). Is it like the equations of motion calculated at $x=2$ and $x=10$ are the same? Hopefully, at some point, you might as well include explanation why inertial frame is homogeneous and non-inertia frame inhomogeneous? in non-inertial frame, the equations of motions would be different at $x=2$ and $x=10$? why?

EXTRA

Why do we call non-inertial frame inhomogeneous space ? Imagine the ball put on a huge table on a uniform accelerating train car. As the train accelerates, ball moves backwards. so can you tell me how different points that ball passes on the table have different physics law ?

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Set up an experiment. Find the result.

Move the experiment somewhere else and run it again. You will get the same result.

To do this, you must move all the important parts of the experiment. For example, if you drop a rock on earth, it falls. If you move the experiment out into space, it just floats. To do it right, you would have to move the earth too.

The results would not be exactly the same because gravity from the moon and the sun have a small effect. So you really need to move them too. And if you really get precise, everything in the universe has a small effect. So you need to move the whole universe. And if you do that, how do you know you have moved anything? It gets confusing.

But if you just move the earth and the thing you drop, you would find that nothing about space itself is different in the two places. The difficulty is all in setting up two identical experiments.


If Alice is in a rocket in space with the engine pushing her, she is in an accelerated frame of reference. If she drops a rock, the rock falls toward the back of the rocket.

Alice is using a frame of reference where things are motionless if they keep up with the rocket. She sees herself as motionless and the rock as accelerated.

An inertial frame of reference is one with no forces on it. If Bob is floating in space far from earth, a dropped rock does not move. In this frame, $F=ma$. If he ties a string to the rock and pulls on it, the rock accelerates.

Bob can make sense out of the rocket. He sees Alice and the rock accelerating together. When Alice drops the rock, it is left behind. Alice accelerates ahead of it. You can see how it looks to her like the rock is accelerating toward the back.

To Bob, space is isotropic. Bob can face any direction and get the same result from his experiment. Space has no special direction.

Alice does see a special direction. She has to exert a force toward the front of the rocket to hold the rock motionless. If she stops and lets $F=0$, the rock accelerates toward the back.

Alice finds that space is homogeneous. She gets the same result if she moves to a different place in the rocket and drops the rock. This sounds like splitting hairs. But it is sometimes useful to distinguish between isotropic and homogeneous.


Alice wants to do physics too. She wants to use a law like $F=ma$. But $F=ma$ applies in inertial frames, and Alice is ignoring a force that pushes her and everything she sees forward. To make it work, she has to play a trick. She says a fictitious force is pushing everything back. She adds this force to the force she exerts on the rock. They cancel and the total force is $0$. Now $F=ma$ works.

One of Einstein's great insights was that gravity is a fictitious force just like a rocket engine. This is called the equivalence principle. This is the basis of General Relativity, which is a theory of gravity.

Bob cannot do any experiment that tells him whether his rocket is floating in space or falling off a cliff on Earth.

Alice cannot do any experiment that tells her whether her rocket engine is pushing her forward or if the rocket is sitting on earth with the engine off.

This is a bit confusing, because Bob or Alice can just look out a window. But that doesn't count. The idea is that for the space inside the room, the laws of physics are the same whether the acceleration comes from gravity or a rocket engine.

So the surface of the Earth is an accelerated frame of reference.

Space near the earth is not homogeneous or isotropic.

If you do not move very far, space is almost the same. But if you go up, the force of gravity gets weaker. If you go to the other side of the world, the special direction changes.


General relativity is not obvious. It might not have been the simplest example of how space can be inhomogeneous in a non-inertial frame of reference.

It took 300 years to get from the discovery of Newton's laws to the discovery of General relativity. For those 300 years, people have been treating space around earth as homogeneous and isotropic. Gravity has been treated as a real force. This all works just fine in ordinary circumstances. You should think this way too.

General relativity is useful because it explains how mass causes gravity. It explains tiny differences between predictions of Newton's laws and experimental results. Starlight is deflected a tiny fraction of a degree as it passes near the surface of the sun. The orbit of mercury is almost but not quite an ellipse. Time runs very slightly slower on earth than in orbit above. It explains effects produced by extremely strong gravity, such as black holes and gravitational waves.

mmesser314
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  • didn't you say that moving earth and ball only would not exactly be the same ? what then makes you say: "you would find that nothing about space itself is different in the two places" 2. could you read my "extra" in my question ?
  • – Giorgi Lagidze Sep 09 '23 at 14:56
  • Thanks for the amazing answer. To call space isotropic, means everywhere you look, it's the same, but this definition is true wherever we stand inside space. and if so, space being isotropic automatically means space is homogeneous ? – Giorgi Lagidze Sep 10 '23 at 15:13
  • Yes, that is right. – mmesser314 Sep 10 '23 at 16:15
  • But does that mean that if space is isotropic, it's always homogeneous ? i'm told that it's not. – Giorgi Lagidze Sep 10 '23 at 16:17
  • I asked the different question relating to this. - https://physics.stackexchange.com/questions/779711/doubts-about-isotrophy-and-homogeneity-of-space – Giorgi Lagidze Sep 10 '23 at 16:19
  • hey @mmesser314, wanted to ask one thing if you don't mind. When testing isotropy, imagine the following scenario. there's a ball somewhere in space and somewhere close to it, from north, there's a big mass of rock. We drop a ball and see its behaviour. now, to check isotropy, we must drop a ball from different location - (30 degree rotation).If you do that,we won't get isotropy for sure since rock has different influence on it. Does this mean space is non-isotropic or we did the check incorrectly (as if we must have moved the big rock by 30 degree left as well as we did for the ball) ? Thanks – Giorgi Lagidze Oct 30 '23 at 17:22
  • It means you have to rotate everything that is important to the experiment. In this case it would be you, the ball, and the rock. But not the distant stars if their effect is small. If you did a higher precision experiment, you would have to rotate more things. – mmesser314 Oct 30 '23 at 20:04
  • hey, sorry for disturbing you about this once more. I wanted to ask about your answer where you say to move all important parts(i.e move earth and ball both if our experiment is dropping a ball from some height to earth). When you do that(i.e use active transformation that translates earth and ball), that active transformation mathematically of course will give you the same results. So did we really show "space homogeneity" by this ? i don't think so. – Giorgi Lagidze Nov 07 '23 at 20:20
  • I mean, if you do this experiments in real life, sure, but if you use active transformation mathematically, there's no way it will yield different results. so i don't think using active transformation which translates both earth and ball actually confirm space homogeneity. I can't think of the system where moving it in different location would yield the different results. So what's the point of using active transformation for "earth+ball" at all in terms of homogeneity ?What's your thoughts ? – Giorgi Lagidze Nov 07 '23 at 20:20