Questions tagged [wavefunction]

A complex scalar field that describes a quantum mechanical system. The square of the modulus of the wave function gives the probability of the system to be found in a particular state. DO NOT USE THIS TAG for classical waves.

The wavefunction is a complex scalar field that describes a quantum mechanical system. The square of the modulus of the wave function gives the probability of the system to be found in a particular state.

In the Schrödinger Wave formulation of Quantum Mechanics, the wavefunction can be determined by the , which, in it's most general form, can be stated as:

$$\hat H|\Psi\rangle=i\hbar\frac{\mathrm d}{\mathrm d t}|\Psi\rangle$$

In the case of a "Euclidean Hamiltonian" given by the operator $\hat H=\frac{\hat P^2}{2m}+\hat U$, this becomes:

$$\left(\frac{\hat P^2}{2m}+\hat U\right) |\Psi\rangle=i\hbar\frac{\mathrm d}{\mathrm d t}|\Psi\rangle$$

Since the momentum operator $\hat P$, in the position bases, is $-i\hbar\nabla$, the Schrödinger equation becomes $$\left(-\frac{\hbar^2}{2m}\nabla^2+U\right)\Psi= i\hbar\frac{\partial\Psi}{\partial t} $$ with $\Psi=\langle x|\Psi\rangle$.

This is known as the time-independent Schrödinger equation. Note, that as the Hamiltonian used was Euclidean, this equation is in fact non-relativistic. The relativistic version of this equation in Relativistic Quantum Mechanics (and also in , but there it describes spin-1/2 fields) is the .

The wavefunction also appears in Feynman's formulation of Quantum Mechanics. In the Path Integral formulation, a functional, called the phase is associated with each path:

$$\phi = A e^\frac{iS}{\hbar} $$

The Kernel or the Matrix Element, is the path integral of this phase.

$$K(x ) =\int\phi\mbox{ } \mathcal{D}x $$

The wavefunction, finally, is given by:

$$\Psi(x)=\int_{-\infty}^\infty \left(K(x,x_0)\Psi(x_0) \right) \mbox{d} x_0 $$

It is often surprising to many that the absolute value of the phase squared, $|\phi|^2$, is constant for all paths, at $A^2$. However, this actually makes sense, as the position of the particle is initially completely well-defined, so Heisenberg's Uncertainty Principle tells us that we would have no idea about the momentum, and thus no idea about it's future position. However, the next moment, you know absolutely nothing about it's momentum, and so on. This process coarse-grains a particular path, the classical path, which means it is much more probable than the other paths.

The mathematical description of this can be obtained by standard procedures (c.f. Feynman, Hibbs, Styer "Quantum Mechanics and Path Integrals", pg 77 - 79) and the final result is the Schrödinger's Equation.

DO NOT USE THIS TAG for classical waves. Use the tag instead.

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Why is the Horizontal Force Constant in Deriving the One Dimensional Wave Equation

My textbook in deriving the wave equation for a one dimensional elastic string stated that the horizontal direction force is constant.I understand that the horizontal components of the tensions on either side of the element have to be equal since it…
Shawn
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Question on wave function of hydrogen

http://physicsworld.com/cws/article/news/2013/may/23/quantum-microscope-peers-into-the-hydrogen-atom http://io9.com/the-first-image-ever-of-a-hydrogen-atoms-orbital-struc-509684901 they are claimed to be images of the actual wave function of…
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Proof why wave function is continuous

Is there an accurate proof why wave function is continuous? I mean wave function as coefficient of eigen states when representing a state with eigen states, so, I am asking continuity of $\psi(x)=<\psi|x>$. I understand that it is a function of…
Zjjorsia
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Binding energy between an $1s$ electron and its nucleus

I've always thought that the binding energy decreases as the electron moves/jumps away from the nucleus. Then when I see the radial probability distribution for $1s$ electron, there is a probability for finding the electron everywhere. Since the…
AgentS
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For an event that can occur in many ways, why is the wavefunction of the event the sum of wavevfunction for each way separately?

The wavefunction of identical particles is given as: $$\psi_{1,2} (x_1,x_2) = \psi_1(x_1)\psi_2(x_2) + \psi_2(x_1)\psi_1(x_2)$$ . Why is it so? Why is it the sum of the two states? What is the explanation behind this? Yes, I know that wavefunction…
user36790
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Potential Step - Choosing Wavefunctions

http://uqu.edu.sa/files2/tiny_mce/plugins/filemanager/files/4190016/Quantum_Mechanics_1/ch4-virtual-book.pdf On page 2 of the above pdf they describe how they select their wavefunctions. Finding the general solution is easy but they then go on to…
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Does measuring the energy of the particle cause its wave function (psi) to change if psi isn't an eigenfunction of the Hamiltonian?

Does measuring the energy of the particle cause its wave function (psi) to change if psi isn't an eigenfunction of the Hamiltonian? quite confused about this one on when the wave function changes when taking a measurement and when it doesn't. please…
Lalo
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Showing a wavefunction is antisymmetric or symmetric

I want to ask a question about showing whether a wavefunction is symmetric or antisymmetric. Consider the wavefunctio below for the group state for Hydrogen, $H_2$ $\psi_A=1 \sigma_{g}\left(r_{1}\right) 1\sigma_{g}\left(r_{2}\right)[\alpha(1)…
vik1245
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Is there a way to check that a wavefunction is antisymmetric?

Is there a general method to check that a given wavefunction is antisymmetric or not? The solution would be simple for cases such as the single Slater determinant. Exchange the wavefunctions of two single particle wavefunction. If they change sign,…
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Does wave function describe particle annihilation?

I don't study physics, this is a layman question. From some online sources, some probability would be given by squaring the parameters of a wave function. Some sources also claim that wave function describes all the states of an entity. Does wave…
frt132
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Particles' Wave Function Capability

Do all particles have the ability to have a wave state even if they are a part of objects larger than those seen tested in the double slit experiment? Do all particles have the ability to have a wave state even if they are not given energy by being…
zach
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Is it possible to measure the energy of the particle if the wave function psi is not an eigenfunction of the hamiltonian?

my friend and i have been debating the answer to this question could someone help me with this by explaining their answer please :) Is it possible to measure the energy of the particle if the wave function psi is not an eigenfunction of the…
Lalo
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